pilssss tolong bntu sama caranya
LUAS =
Luas Persegi =
S × S
= 21 × 21
= 441 cm²
Luas ½ lingkaran besar =
½ × 22/7 × r × r
= ½ × 22/7 × 14 × 14
= ½ × 22 × 2 × 14
= ½ × 616
= 308 cm²
Luas ½ lingkaran kecil =
½ × 22/7 × r × r
= ½ × 22/7 × 7 × 7
= ½ × 22 × 7
= 11 × 7
= 77 cm²
Jadi Luas daerah yang diarsir
= 441 - (308 + 77)
= 441 - 385
= 56 cm²
KELILING =
Keliling ½ lingkaran besar =
½ × 22/7 × d
= ½ × 22/7 × 28
= ½ × 88
= 44 cm
Keliling ½ lingkaran kecil =
½ × 22/7 × d
= ½ × 22/7 × 14
= ½ × 44
= 22 cm²
Jadi keliling daerah yg diarsir adalah
44 + 22 = 66 cm
JAWABAN AKHIR
LUAS = 56 cm²
KELILING = 66 cm
[answer.2.content]![Matematika [tex]{\mathcal Qz}[/tex]<br />[tex]{\sf f(x) = x!! + x² - 10}[/tex]<br />[tex]{\sf f(5) =?}[/tex]](https://1.bp.blogspot.com/-FxxoZkxtk_U/WKAvV2Gd6iI/AAAAAAAACd0/UTrLC-1x23k1E0oqRLErM2XliW2XDiBlQCK4B/s1600/dif.jpg "Matematika [tex]{\mathcal Qz}[/tex]<br />[tex]{\sf f(x) = x!! + x² - 10}[/tex]<br />[tex]{\sf f(5) =?}[/tex]")
