Matematika Q. Sec[tex]\displaystyle \sf\lim\limits_{x~\to~3} ~~ \frac{2x^2 + 2}{5}~=~.~.~.~[/tex]​

janelleabbottulv – March 08, 2023

Q. Sec

[tex]\displaystyle \sf\lim\limits_{x~\to~3} ~~ \frac{2x^2 + 2}{5}~=~.~.~.~[/tex]

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Penyelesaian:

[tex]\displaystyle \sf\lim\limits_{x~\to~3} ~~ \frac{2x^2 + 2}{5}~=[/tex]

[tex] = \frac{2(3)^2 + 2}{5}[/tex]

[tex] = \frac{2(3 \times 3) + 2}{5}~[/tex]

[tex] = \frac{18 + 2}{5}[/tex]

[tex] = \frac{20}{5} [/tex]

[tex] = 4[/tex]

Semoga Membantu CMIW^_^

[tex] = \frac{2 \times 3^{2} + 2 }{5} \: \: \\ = \frac{20}{5} \\ = 4[/tex]

Jadi, hasil akhirnya adalah 4.

Semoga membantu :)

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